-8t^2+-6t+9=0

Solution for -8t^2+-6t+9=0 equation:

-8t^2+-6t+9=0

We add all the numbers together, and all the variables

-8t^2-6t=0

a = -8; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-8)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-8}=\frac{0}{-16}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-8}=\frac{12}{-16}
=-3/4
$